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High-Pass Filter Calculator

First-order RC high-pass cutoff fc=1/(2πRC) and optional |H(f)|. Twin of the LPF calculator.

Instant result
Result
—

Enter values to calculate.

Inputs—
Mode—
Formula—
Trust summary CVP VERIFIED · CVP protocol 1.0.0-proposed · Engineering assurance
Input interpretation
Enter values to calculate.
Result
—
Assurance
Engineering
Declared partition coverage
PASS · 3/3 declared partitions (solve-rc, with-f, invalid-domain) · Matrix
Known limitations
  • First-order RC HPF only
  • Core CVP does not include live graph, viewport, or pointer interaction.
Model
First-order RC HPF cutoff and optional magnitude.
Scope
Ideal first-order RC
Verification
Engine tested · Source checked · v1.0.0 · CVP VERIFIED · CVP protocol 1.0.0-proposed · Engineering assurance· View Manifest · CVP overview · Specification
Versions
Calculation 1.0.0 · CVP protocol 1.0.0-proposed
CVP identity
2/2 property · digest de35114a5396
Legacy regression
6/6 tests · Production surface contract 3/3
Reference
O1 model · O2 expected_values · O2 numerical_behavior
Interfaces
PASS · UI (SSR) / REST / MCP — ui-ssr is query-result HTML, not a live browser session.
Supplemental domain review
Internal · Pass · electrical-engineer
Named expert review
Not performed
CVP suite
2/2 golden · 2/2 CVP boundary · 2/2 invalid · 2/2 property · 1/1 cross-interface · 1/1 CVP contract · Manifest
Sources
  • Horowitz & Hill — The Art of Electronics — RC filters
  • IEC 60050 — IEV — High-pass filter
Sources
Evidence
2 legacy golden · 2 legacy boundary · legacy regression suite · 2/2 oracle-backed golden · 2/2 invalid · Artifact integrity PASS · CalculatorX electrical review
This calculator CURRENT · Public schema 1.0.0 matches · Semantic contract ✓ · Production attested · Public/cache ✓ · Origin ✓
Semantic contract
PASS
Full verification

Manifest identity, reference classes, interfaces, suite, and production records.

Formulas

Core equations used by this calculator.

Cutofffc = 1 / (2πRC)
Magnitude|H| = (f/fc) / √(1+(f/fc)²)
iIdeal lumped RC; same fc relation as LPF, different |H|.

How to use

1

Enter any two of R, C, and fc

Leave the unknown blank to solve it. Values must be > 0.

2

Optional: enter evaluation frequency f

If provided, magnitude |H| and H_dB are shown at that frequency.

3

Read cutoff and response

fc = 1/(2πRC) for a first-order RC high-pass.

Example calculations

Common configurations with formula and result.

ϟ

10 kΩ · 1 µF

fc ≈ 15.92 Hz

fc=1/(2πRC)
fc ≈ 15.915 Hz

High-Pass Filter calculator specification

Version 1.0.0 · Engine tested · Supplemental domain review · Internal · 2026-08-08

Calculation status

Review policy · Evidence · Reviewed by CalculatorX electrical review (electrical-engineer)

Definition
A first-order RC high-pass has fc = 1/(2πRC). Magnitude |H| = u/√(1+u²) with u = f/fc (−3 dB at fc).
What it calculates
First-order RC HPF cutoff and optional magnitude.
Inputs
  • Any two of R, C, fc
  • optional f
Outputs
  • R
  • C
  • fc
  • H_lin?
  • H_dB?
Formula
fc=1/(2πRC); |H|=u/√(1+u²)
Assumptions
  • Ideal first-order RC
Units
  • Ω, F, Hz
Boundary conditions
  • <2 of R/C/fc → NEEDS_TWO_INPUTS
Example
10k·1µF → fc≈15.92 Hz
Validation cases

1 published on this page · 6/6 tests · Production surface contract 3/3 · View evidence

  • R=10k,C=1u → fc≈15.915494
Sources
  • Horowitz & Hill — The Art of Electronics — RC filters
    Supports: First-order HPF magnitude
  • IEC 60050 — IEV — High-pass filter
    Supports: First-order RC HPF cutoff identity
Last reviewed
2026-08-08
Reviewed by
CalculatorX electrical review (electrical-engineer)
Calculation version
1.0.0

Background

Interpretation and common distinctions.

Size a first-order RC high-pass filter.

Default: 10 kΩ · 1 µF → fc ≈ 15.92 Hz.

Agent / API notes

Capability id: electrical.hpf · tool id: hpf · pin 1.0.0.

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Frequently asked questions

Key distinctions behind the calculation.

How does this differ from LPF?

Cutoff formula is the same; HPF passes high frequencies (|H|→1 as f→∞) while LPF passes DC.